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1 \section{Problem 4}
2 {\em
3 Seven integer variables $a_1; a_2; a_3; a_4; a_5; a_6; a_7$ are given, for
4 which the initial value of $a_i$ is $i$ for $i=1,\ldots,I$ where $I=7$. The
5 following steps are defined: choose $i$ with $1<i<7$ and execute
6 $$a_i:=a_{i-1}+a_{i+1}$$
7 that is, $a_i$ gets the sum of the values of its
8 neighbors and all other values remain unchanged. Show how it is possible that
9 after a number of steps a number of steps a number $\geq 50$ occurs at least
10 twice in $a_1; a_2; a_3; a_4; a_5; a_6; a_7$.
11 }
12
13 \subsection{Formal definition}
14 For every variable $a_i$ for $i\in I$ where $I=\{1,\ldots,7\}$ we define
15 variables for all iterations $n$ for $n\in N$ where $N=\{1,\ldots,K\}$ for a
16 fixed $K$ and call the $a_i^n$.
17
18 This leads to the following formalization where we minimize $K$.
19
20 \begin{align}
21 \bigwedge_{i\in I}a_i^0=i\wedge\\
22 \bigwedge_{n\in N}\Biggl(\bigvee_{i\in I}\Bigl(
23 & j\neq 0\wedge j\neq I\wedge
24 a_i^n=a_{i-1}^{n-1}+a_{i+1}^{n-1}\wedge\\
25 \nonumber & \bigwedge_{j\in I}i\neq j\wedge
26 a_j^n=a_j^{n-1}\Bigr)\Biggr)\\
27 \bigvee_{i\in I}\Biggl(
28 & a_i^N\geq50\wedge
29 \bigvee_{j\in I}i\neq j\wedge a_i^N=a_j^N\Biggr)
30 \end{align}
31
32 Every number subformula describes either the precondition, program or
33 postcondition.
34 \begin{enumerate}
35 \setcounter{enumi}{15}
36 \item Makes sure all $a_i^0$ have the specified initial value.
37 \item Makes sure that in one iteration zero or one of the $a_i$ becomes
38 the sum of its neighbors by stating in the first part that
39 $a_i^n=a_{i-1}^{n-1}+a_{i+1}^{n-1}$ for $i$ not being $0$ or
40 $I$. The second part states that all other $a_i$ stay the same.
41 \item Makes sure that the postcondition is satisfied by stating there
42 are $a_i$ and $a_j$ where $i\neq j$ and $a_i^N=a_j^N$ and both
43 are bigger then $50$
44 \end{enumerate}
45
46 \subsection{SMT format solution}
47 The formula is easily convertable via a Python script to SMT format by literal
48 conversion. The script optimizes a little bit from the original formula by
49 leaving out the $i=j$ comparison in subformula 17 and 18 by removing them from
50 the set looped over. The script also optimizes by not checking variables
51 $a_0^n$ and $a_I^n$ since they always stay the same anyways. The minimization
52 is done by incrementing variable $N$ every time the current $N$ yields unsat
53 with a bash script shown in Listing~\ref{listing:4.bash}.
54
55 \lstinputlisting[language=bash,firstline=58,
56 caption={Iteratively find the shortest solution for problem 4},
57 label={listing:4.bash}]{src/a4.bash}
58
59 \subsection{Solution}
60 The bash script finds and shows the minimal solution in which the postcondition
61 is satisfied for $N=10$. Finding this solution takes less then $20$ seconds and
62 is shown in Table~\ref{tab:s4}.
63
64 Every line in the table represents the iteration and the bold items represent
65 the step chosen in transition between iterations.
66 \begin{table}[H]
67 \centering
68 \input{a4.tex}
69 \caption{Solution table for problem 4}
70 \label{tab:s4}
71 \end{table}